Electrostatics

JEE Main level, single correct, medium

281 of 311

Question 281 of 311

Match List I with List II

Chose the correct answer from the options given below

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Answer: (C) A−IV,B−III,C−I,D−IIA-IV,B-III,C-I,D-II

Ampere – Maxwell law
→∮B⃗⋅dl⃗=μ0ic+μ0ϵ0dϕEdt\rightarrow \oint \vec{B}\cdot d\vec{l}={\mu }_{0}{i}_{c}+{\mu }_{0}{\epsilon }_{0}\dfrac{d{\phi }_{E}}{dt}
Faraday law
→∮E⃗⋅dl⃗=dϕBdt\rightarrow \oint \vec{E}\cdot d\vec{l}=\dfrac{d{\phi }_{B}}{dt}
Gauss’ law for electricity →∮E⃗⋅dA⃗=Qϵ0\rightarrow \oint \vec{E}\cdot d\vec{A}=\dfrac{Q}{{\epsilon }_{0}}
Gauss' law for magnetism →∮B⃗⋅dA⃗=0\rightarrow \oint \vec{B}\cdot d\vec{A}=0

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