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Oscillations

JEE Main level, numerical answer, medium

35 of 194

Question 35 of 194

Two simple harmonic motion, are represented by the equations
${y}_{1}=10\sin \left(3\pi t+\dfrac{\pi }{3}\right);{y}_{2}=5(\sin 3\pi t+\sqrt{3}\cos 3\pi t)$
Ratio of amplitude of ${y}_{1}$ to ${y}_{2}=x:1$ . The value of $x$ is

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Answer: 1

{y}_{1}=10\sin \left(3\pi t+\dfrac{\pi }{3}\right)

{y}_{2}=5[\sin 3\pi t+\sqrt{3}\cos \pi t]

{y}_{2}=10\sin \left(3\pi t+\dfrac{\pi }{3}\right) \Rightarrow \dfrac{{A}_{2}}{{A}_{1}}=\dfrac{10}{10}=1

JEE Main question paper PDF

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JEE Main 2025 Apr 2 Shift 1 question paper

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JEE Main Physics practice question on Oscillations (Simple Harmonic Motion), with the answer and a step-by-step solution. Scan a question from your own book or paper to get a whiteboard video.