Oscillations

JEE Main level, single correct, medium

39 of 194

Question 39 of 194

A particle starts executing simple harmonic motion (SHM)(SHM) of amplitude aa and total energy E.E. At any instant, its kinetic energy is 3E4\dfrac{3E}{4}, then its displacement yy is given by:

Show answer and solution

Answer: (D) y=a2y=\dfrac{a}{2}

E=12Ka2E=\dfrac{1}{2}K{a}^{2}
3E4=12K(a2−y2)v\dfrac{3E}{4}=\dfrac{1}{2}K\left({a}^{2}-{y}^{2}\right)v
34×12Ka2=12K(a2−y2)\dfrac{3}{4}\times \dfrac{1}{2}K{a}^{2}=\dfrac{1}{2}K\left({a}^{2}-{y}^{2}\right)
y2=a2−3a24{y}^{2}={a}^{2}-\dfrac{3{a}^{2}}{4}
y=a2y=\dfrac{a}{2}

JEE Main question paper PDF

Open a shift to read the full paper on this page, or download it.

JEE Main 2025 Apr 2 Shift 1 question paper

Open Download PDF

Opening paper…

Explain it as a whiteboard videoStep-by-step, in Hinglish or English. Your first video needs no login.Solved it on paper but got it wrong?Upload a photo of your working. Mistake Doctor marks the exact line that broke.
See it move: Simple pendulum simulationDrag the sliders and watch the numbers in this question change.

More Physics practice

JEE Main Physics practice question on Oscillations (Simple Harmonic Motion), with the answer and a step-by-step solution. Scan a question from your own book or paper to get a whiteboard video.