Question 61 of 194

The displacement $y(t)=A \sin (\omega t+\phi)$ of a pendulum for $\phi=\frac{2 \pi}{3}$ is correctly represented by

ABCD

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Answer: (A)

Displacement $y(t)=A \sin (\mathrm{w} t+\phi)$ [Given]
For $\phi=\frac{2 \pi}{3}$
at $t=0 ; y=A \sin \phi=A \sin \frac{2 \pi}{3}$
$$=A \sin 120^{\circ}=0.87 \mathrm{~A}\left[\because \sin 120^{\circ} \simeq 0.866\right]$$
Graph (a) depicts $y=0.87 A$ at $t=0$

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