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Oscillations

JEE Main level, single correct, medium

68 of 194

Question 68 of 194

Two simple harmonic motions are represented by the equation $\mathrm{y}_1=0.1$ $\sin \left(100 \pi t+\frac{\pi}{3}\right)$ and $y_2=0.1 \cos \pi t$ . The phase difference of the velocity of particle 1 w.r.t. the velocity of the particle 2 is

Show answer and solution

Answer: (A) $-\pi / 6$

Phase difference

(\phi)=99 \pi \mathrm{t}+\pi / 3-\pi / 2

t=0, \phi=-\pi / 6

JEE Main question paper PDF

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JEE Main 2025 Apr 2 Shift 1 question paper

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JEE Main Physics practice question on Oscillations (Simple Harmonic Motion), with the answer and a step-by-step solution. Scan a question from your own book or paper to get a whiteboard video.