Oscillations

JEE Main level, single correct, medium

88 of 194

Question 88 of 194

The variation of displacement with time of a particle executing free simple harmonic motion is shown in the figure.

The potential energy
U(x)U(x) versus time (t)\left(t\right) plot of the particle is correctly shown in figure:

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Answer: (D)

Considering→\rightarrow Spring −- mass system
x=x0sin⁡ωtx={x}_{0}\sin \omega t
P.E.=12kx2=12kxo2sin⁡2ωt=csin⁡2ωtP.E.=\dfrac{1}{2}k{x}^{2}=\dfrac{1}{2}kx{o}^{2}{\sin }^{2}\omega t=c{\sin }^{2}\omega t
⇒PE=(1−cos⁡2ωt2)\Rightarrow PE=\left(\dfrac{1-\cos 2\omega t}{2}\right)

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