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Oscillations

JEE Main level, single correct, medium

90 of 194

Question 90 of 194

For what value of displacement the kinetic energy and potential energy of a simple harmonic oscillation become equal?

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Answer: (C) $x=\pm \dfrac{A}{\sqrt{2}}$

KE=PE

\dfrac{1}{2}m{\omega }^{2}\left({A}^{2}-{x}^{2}\right)=\dfrac{1}{2}m{\omega }^{2}{x}^{2}

{A}^{2}-{x}^{2}={x}^{2}

2{x}^{2}={A}^{2}

x=\pm \dfrac{A}{\sqrt{2}}

JEE Main question paper PDF

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JEE Main 2025 Apr 2 Shift 1 question paper

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JEE Main Physics practice question on Oscillations (Energy of Simple Harmonic Motion), with the answer and a step-by-step solution. Scan a question from your own book or paper to get a whiteboard video.