Oscillations

JEE Main level, single correct, medium

134 of 194

Question 134 of 194

A hoop and a solid cylinder of same mass and radius are made of a permanent magnetic material with their respective axes. But the magnetic moment of hoop is twice of solid cylinder. They are placed in a uniform magnetic field in such a manner that their magnetic moments make a small angle with the field. If the oscillation periods of hoop and cylinder are Th{T}_{h} and Tc{T}_{c} respectively, then:

Show answer and solution

Answer: (B) Th=Tc{T}_{h}={T}_{c}

Time period of any magnetic body place in an external magnetic field is:-

T=2πIMBT=2\pi \sqrt{\dfrac{I}{MB}}

Thoop=2πmR2MB{T}_{hoop}=2\pi \sqrt{\dfrac{m{R}^{2}}{MB}} ...... (1)(1) Ihoop=mR2{I}_{hoop}=m{R}^{2}

Tc=2πmR22M2(B){T}_{c}=2\pi \sqrt{\dfrac{\dfrac{m{R}^{2}}{2}}{\dfrac{M}{2}\left(B\right)}} ...... (2)(2) ISolidcylinder=mR22{I}_{Solidcylinder}=\dfrac{m{R}^{2}}{2}

From
(1)(1) and (2)(2)

Th=Tc{T}_{h}={T}_{c}

JEE Main question paper PDF

Open a shift to read the full paper on this page, or download it.

JEE Main 2025 Apr 2 Shift 1 question paper

Open Download PDF

Opening paper…

Explain it as a whiteboard videoStep-by-step, in Hinglish or English. Your first video needs no login.Solved it on paper but got it wrong?Upload a photo of your working. Mistake Doctor marks the exact line that broke.
See it move: Simple pendulum simulationDrag the sliders and watch the numbers in this question change.

More Physics practice

JEE Main Physics practice question on Oscillations (Time Period and Frequency), with the answer and a step-by-step solution. Scan a question from your own book or paper to get a whiteboard video.