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Oscillations

JEE Main level, single correct, medium

194 of 194

Question 194 of 194

A particle of mass $m$ is attached to a spring (of spring constant $k$ ) and has a natural angular frequency $\omega_0$ . An external force $F(t)$ proportional to $\cos \omega t\left(\omega \neq \omega_0\right)$ is applied to the oscillator. The time displacement of the oscillator will be proportional to

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Answer: (B) $\frac{1}{m\left(\omega_0^2-\omega^2\right)}$

For forced oscillations, the displacement is given by

\mathrm{x}=\mathrm{A} \sin (\omega \mathrm{t}+\phi) \text { with } \mathrm{A}=\frac{\mathrm{F}_0 / \mathrm{m}}{\omega_0^2-\omega^2}

JEE Main question paper PDF

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JEE Main 2025 Apr 2 Shift 1 question paper

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More Physics practice

JEE Main Physics practice question on Oscillations (Angular oscillations), with the answer and a step-by-step solution. Scan a question from your own book or paper to get a whiteboard video.