Semiconductors

JEE Main level, numerical answer, medium

55 of 209

Question 55 of 209

In the circuit shown below, maximum Zener diode current will be _____ mAmA.

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Answer: 9

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Current through load resistor is IL=60V10000Ω=0.006A{I}_{L}=\dfrac{60V}{10000\Omega }=0.006A and current through 4000Ω4000\Omega resistor is I=(120−60)V4000Ω=0.015AI=\dfrac{\left(120-60\right)V}{4000\Omega }=0.015A
Thus, maximum current through Zener diode is IZ=I−IL{I}_{Z}=I-{I}_{L}
=0.015−0.006=0.009A=9mA=0.015-0.006=0.009A=9mA

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