Semiconductors

JEE Main level, numerical answer, medium

56 of 209

Question 56 of 209

Two ideal diodes are connected in the network as shown in figure. The equivalent resistance between AA and BB is _____ Ω.\Omega .

Show answer and solution

Answer: 25

If AA is connected to a higher potential compared to BB, then left diode will be in forward bias and hence will not offer any resistance also the right diode will be in reverse bias and hence it will behave as open key. Therefore, the modified circuit will be as given below.

∴∴ Equivalent resistance =202+15=25Ω=\dfrac{20}{2}+15=25\Omega

JEE Main question paper PDF

Open a shift to read the full paper on this page, or download it.

JEE Main 2025 Apr 2 Shift 1 question paper

Open Download PDF

Opening paper…

Explain it as a whiteboard videoStep-by-step, in Hinglish or English. Your first video needs no login.Solved it on paper but got it wrong?Upload a photo of your working. Mistake Doctor marks the exact line that broke.
See it move: Semiconductors, diodes and logic gates simulationDrag the sliders and watch the numbers in this question change.

More Physics practice

JEE Main Physics practice question on Semiconductors (Diodes), with the answer and a step-by-step solution. Scan a question from your own book or paper to get a whiteboard video.