Semiconductors

JEE Main level, numerical answer, medium

64 of 209

Question 64 of 209

In the given circuit, the value of current IL{I}_{L} will be _____ mA.mA. (When RL=1kΩ{R}_{L}=1k\Omega)

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Answer: 5


Potential drop across the branch containing load resistance will be 5V5V due to Zener diode. Therefore, potential drop across 800Ω800\Omega will be, 10V−5V=5V10V-5V=5V.
Now, current through battery will be,
I=5800×1000I=\dfrac{5}{800}\times 1000 =6.25mA=6.25mA
Current through load will be,
IL=51000A{I}_{L}=\dfrac{5}{1000}A
=5mA=5mA

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