Semiconductors

JEE Main level, numerical answer, medium

70 of 209

Question 70 of 209

For the given circuit, the power across zener diode is _____ mWmW.

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Answer: 120


i1=141×103=14mA{i}_{1}=\dfrac{14}{1\times {10}^{3}}=14mA
i3=105×103=2mA{i}_{3}=\dfrac{10}{5\times {10}^{3}}=2mA
i2=i1−i3=12mA{i}_{2}={i}_{1}-{i}_{3}=12mA
Power consumed in zener diode
=V×i=0.12W=120mW=V\times i=0.12W=120mW

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