Semiconductors

JEE Main level, numerical answer, medium

85 of 209

Question 85 of 209

In the circuit shown below, is working as a 8Vdc8Vdc regulated voltage source. When 12V12V is used as an input, the power dissipated (in mWmW ) in each diode is (Considering both zener diodes are identical)

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Answer: 40

i=(12−8)(200+200)A=4400=10−2Ai=\dfrac{\left(12-8\right)}{\left(200+200\right)}A=\dfrac{4}{400}={10}^{-2}A
Power loss in each diode=(4)(10−2)W=40mW=\left(4\right)\left({10}^{-2}\right)W=40mW

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