Question 95 of 209

In the given circuit the current through zener diode is:

A$3.3mA$B$2.5mA$C$5.5mA$D$6.7mA$

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Answer: (A) $3.3mA$

${V}_{AB}=10V$$∴{V}_{BC}=5V$, the current in ${R}_{1}={I}_{1}=\dfrac{5}{500}$
$\Rightarrow {I}_{1}=10mA$. Current in ${R}_{2}={I}_{2}=\dfrac{10}{1500}$$\Rightarrow {I}_{2}=\dfrac{20}{3}mA$

Current in zener diode = ${I}_{1}-{I}_{2}=\left(10-\dfrac{20}{3}\right)mA=\dfrac{10}{3}mA$

JEE Main Physics practice question on Semiconductors (Diodes), with the answer and a step-by-step solution. Scan a question from your own book or paper to get a whiteboard video.