Semiconductors

JEE Main level, single correct, medium

133 of 209

Question 133 of 209

Identify the correct truth table of the given logic circuit.

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Answer: (D) \(\begin{array}{|c|c|c|} \hline A & B & Y \\ \hline 0 & 0 & 0 \\ \hline 0 & 1 & 0 \\ \hline 1 & 0 & 1 \\ \hline 1 & 1 & 0 \\ \hline \end{array}\)

Analysing the logic circuit:

The output is Y=A⋅A⋅B‾Y = A \cdot \overline{A \cdot B}

=A⋅(Aˉ+Bˉ)= A \cdot (\bar{A} + \bar{B})

=AAˉ+ABˉ=0+ABˉ=ABˉ= A\bar{A} + A\bar{B} = 0 + A\bar{B} = A\bar{B}

Truth table:
A=0,B=0⇒Y=0A=0, B=0 \Rightarrow Y=0
A=0,B=1⇒Y=0A=0, B=1 \Rightarrow Y=0
A=1,B=0⇒Y=1A=1, B=0 \Rightarrow Y=1
A=1,B=1⇒Y=0A=1, B=1 \Rightarrow Y=0

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