Semiconductors

JEE Main level, single correct, medium

158 of 209

Question 158 of 209

The output from a NAND gate having inputs A and B given below will be,

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Answer: (B)

The output of NAND gate is
Y=(AB)′Y=(AB{)}^{'}.
The truth table is

ABY001011101110\begin{matrix}A & B & Y \\ 0 & 0 & 1 \\ 0 & 1 & 1 \\ 1 & 0 & 1 \\ 1 & 1 & 0\end{matrix}
YY would be zero only when both A and B are 11 . Clearly, for all other input conditions the output will be 11. Hence, this is the right option.

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