Question 173 of 209

Four NOR gates are connected as shown in figure. The truth table for the given figure is :

A$\begin{matrix}A & B & Y \\ 0 & 0 & 1 \\ 0 & 1 & 0 \\ 1 & 0 & 1 \\ 1 & 1 & 0\end{matrix}$B$\begin{matrix}A & B & Y \\ 0 & 0 & 0 \\ 0 & 1 & 1 \\ 1 & 0 & 1 \\ 1 & 1 & 0\end{matrix}$C$\begin{matrix}A & B & Y \\ 0 & 0 & 1 \\ 0 & 1 & 0 \\ 1 & 0 & 0 \\ 1 & 1 & 1\end{matrix}$D$\begin{matrix}A & B & Y \\ 0 & 0 & 0 \\ 0 & 1 & 1 \\ 1 & 0 & 0 \\ 1 & 1 & 1\end{matrix}$

Show answer and solution▾

Answer: (C) $\begin{matrix}A & B & Y \\ 0 & 0 & 1 \\ 0 & 1 & 0 \\ 1 & 0 & 0 \\ 1 & 1 & 1\end{matrix}$

$y=\bar{\bar{(A+\bar{A+B})}+\bar{(B+\bar{A+B})}}$
$y=(A+\bar{A+B})\cdot (B+\bar{A+B})$
$\begin{matrix}A & B & Y \\ 0 & 0 & 1 \\ 1 & 1 & 1 \\ 0 & 1 & 0 \\ 1 & 0 & 0\end{matrix}$

JEE Main Physics practice question on Semiconductors (Logic gates), with the answer and a step-by-step solution. Scan a question from your own book or paper to get a whiteboard video.