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Semiconductors

JEE Main level, single correct, medium

181 of 209

Question 181 of 209

Draw the output signal $Y$ in the given combination of gates.

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Answer: (A)

According to gates by Demorgan's law

\bar{\bar{A}+B}=A\cdot \bar{B}

By observation.

JEE Main question paper PDF

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JEE Main 2025 Apr 2 Shift 1 question paper

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More Physics practice

SemiconductorsWhich of the following logic gates provides output $Y = 0$ only when both inputs $A=1$ and $B=1$ ?
SemiconductorsIn the given digital logic circuit network consisting of a NAND gate followed by a NOT gate, if inputs are $A=1$ and $B=1$ , the final output $Y$ will be:
SemiconductorsIn a forward biased P-N junction diode, the depletion layer width:
SemiconductorsIn a common emitter NPN transistor amplifier, input resistance is $1\,\text{k}\Omega$ and load resistance is $10\,\text{k}\Omega$ . If $\beta=50$ , voltage gain is:
SemiconductorsA light emitting diode (LED) is fabricated using GaAs semiconducting material whose band gap is $1.42 \mathrm{eV}$ . The wavelength of light emitted from the LED is :
SemiconductorsThe acceptor level of a p-type semiconductor is $6 \mathrm{eV}$ . The maximum wavelength of light which can create a hole would be : Given $\mathrm{hc}=1242 \mathrm{eV} \mathrm{nm}$ .

JEE Main Physics practice question on Semiconductors (Logic gates), with the answer and a step-by-step solution. Scan a question from your own book or paper to get a whiteboard video.

Draw the output signal YYY in the given combination of gates.

JEE Main question paper PDF

More Physics practice

Draw the output signal $Y$ in the given combination of gates.