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Semiconductors

JEE Main level, single correct, medium

194 of 209

Question 194 of 209

Truth table for the given circuit will be

Show answer and solution

Answer: (C) $\begin{array}{cc|c} x & y & z \\ \hline 0 & 0 & 1 \\ 0 & 1 & 1 \\ 1 & 0 & 1 \\ 1 & 1 & 1 \end{array}$

Truth table of the circuit is as follows

\begin{array}{|c|c|c|c|c|c|} \hline x & y & \bar{x} & a=x \cdot y & b=\bar{x} \cdot y & z=\overline{a \cdot b} \\ \hline 0 & 0 & 1 & 0 & 0 & 1 \\ \hline 0 & 1 & 1 & 0 & 1 & 1 \\ \hline 1 & 0 & 0 & 0 & 0 & 1 \\ \hline 1 & 1 & 0 & 1 & 0 & 1 \\ \hline \end{array}

JEE Main question paper PDF

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JEE Main 2025 Apr 2 Shift 1 question paper

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More Physics practice

JEE Main Physics practice question on Semiconductors (Logic gates), with the answer and a step-by-step solution. Scan a question from your own book or paper to get a whiteboard video.