Current Electricity

JEE Main level, numerical answer, medium

102 of 380

Question 102 of 380

To determine the resistance (R)(R) of a wire, a circuit is designed below. The V−IV-I characteristic curve for this circuit is plotted for the voltmeter and the ammeter readings as shown in figure. The value of RR is ______ Ω\Omega.

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Answer: 2500

 Req =104R104+RE=4V,I=2mAI=EReq⇒2×10−3=4(104+R)104R⇒20R=40000+4R\begin{aligned} & \text { Req }=\frac{10^4 R}{10^4+R} \\ & E=4 V, I=2 m A \\ & I=\frac{E}{R e q} \Rightarrow 2 \times 10^{-3}=\frac{4\left(10^4+R\right)}{10^4 R} \\ & \Rightarrow 20 R=40000+4 R\end{aligned}
16R=40000R=2500Ω\begin{aligned} & 16 R=40000 \\ & R=2500 \Omega\end{aligned}

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