Electrostatics

JEE Main level, single correct, medium

256 of 311

Question 256 of 311

An electric dipole is placed on x−x-axis in proximity to a line charge of linear charge density 3.0×10−6Cm−1.3.0\times {10}^{-6}C{m}^{-1}. Line charge is placed on z−z-axis and positive and negative charge of dipole is at a distance of 10mm10mm and 12mm12mm from the origin respectively. If total force of 4N4N is exerted on the dipole, find out the amount of positive or negative charge of the dipole.

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Answer: (D) 4.44μC4.44\mu C


r=10mm,x=2,r=10mm,x=2,
∣F⃗q∣=2kλr⋅q\left|{\vec{F}}_{q}\right|=\dfrac{2k\lambda }{r}\cdot q
∣F⃗−q∣=2kλr+x⋅q\left|{\vec{F}}_{-q}\right|=\dfrac{2k\lambda }{r+x}\cdot q
∣F⃗net∣=2kλq⋅xr(r+x)\left|{\vec{F}}_{net}\right|=\dfrac{2k\lambda q\cdot x}{r(r+x)}
4=2×9×109×3×10−6×q×2mm10mm.12mm4=\dfrac{2\times 9\times {10}^{9}\times 3\times {10}^{-6}\times q\times 2mm}{10mm.12mm}
⇒q=4.44μC\Rightarrow q=4.44\mu C

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