Electrostatics

JEE Main level, single correct, medium

305 of 311

Question 305 of 311

Four closed surfaces and corresponding charge distributions are shown below.



Let the respective electric fluxes through the surfaces be ϕ1,ϕ2,ϕ3{\phi }_{1},{\phi }_{2},{\phi }_{3} and ϕ4{\phi }_{4}. Then:

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Answer: (D) ϕ1=ϕ2=ϕ3=ϕ4{\phi }_{1}={\phi }_{2}={\phi }_{3}={\phi }_{4}

By Gauss law,
ϕ=∑qenclosedϵo\phi =\dfrac{\sum {q}_{enclosed}}{{ϵ}_{o}}

∑qenclosed\sum {q}_{enclosed} is same in all cases.

⇒ ϕ\phi will be same in all four cases

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