Question 15 of 194
A particle is doing simple harmonic motion of amplitude and time period . The maximum velocity of the particle is _______ .
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Answer: 12
We know
$\begin{aligned}
\mathrm{V}_{\max } & =\omega \mathrm{A} \quad \text { at mean position } \\
& =\frac{2 \pi}{\mathrm{T}} \mathrm{A}=\frac{2 \pi}{\pi} \times 0.06=0.12 \mathrm{~m} / \mathrm{sec} \\
\mathrm{V}_{\max } & =12 \mathrm{~cm} / \mathrm{sec}
\end{aligned}$
$\begin{aligned}
\mathrm{V}_{\max } & =\omega \mathrm{A} \quad \text { at mean position } \\
& =\frac{2 \pi}{\mathrm{T}} \mathrm{A}=\frac{2 \pi}{\pi} \times 0.06=0.12 \mathrm{~m} / \mathrm{sec} \\
\mathrm{V}_{\max } & =12 \mathrm{~cm} / \mathrm{sec}
\end{aligned}$