Semiconductors

JEE Main level, numerical answer, medium

68 of 209

Question 68 of 209

A zener diode of power rating 2W2W is to be used as a voltage regulator. If the zener diode has a breakdown of 10V10V and it has to regulate voltage fluctuated between 6V6V and 14V14V, the value of Rs{R}_{s} for safe operation should be _____ Ω\Omega .

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Answer: 20

For diode P=ViP=Vi
i=PV=210=0.2Ai=\dfrac{P}{V}=\dfrac{2}{10}=0.2A
Now for
Vs=14V{V}_{s}=14V
Voltage drop across
Rs=14−10=4V{R}_{s}=14-10=4V
Thus,
V=iRsV={iR}_{s}
Rs=40.2=20Ω{R}_{s}=\dfrac{4}{0.2}=20\Omega

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