Question 138 of 209

Consider the following logic circuit.

The output is $\mathrm{Y}=0$ when :

A$\mathrm{A}=1$ and $\mathrm{B}=1$B$\mathrm{A}=0$ and $\mathrm{B}=1$C$\mathrm{A}=1$ and $\mathrm{B}=0$D$\mathrm{A}=0$ and $\mathrm{B}=0$

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Answer: (A) $\mathrm{A}=1$ and $\mathrm{B}=1$

$\begin{aligned}
& \mathrm{Y}_1=\mathrm{A} \cdot \mathrm{~B}, \mathrm{Y}_2=\overline{\mathrm{A}}+\mathrm{B} \\
& \mathrm{Y}=\overline{\mathrm{Y}_1 \cdot \mathrm{Y}_2}=\overline{\mathrm{Y}}_1+\overline{\mathrm{Y}}_2 \\
& \mathrm{Y}=\overline{\mathrm{A} \cdot \mathrm{~B}}+\overline{\mathrm{A}+\mathrm{B}} \\
& \mathrm{Y}=\overline{\mathrm{A}}+\overline{\mathrm{B}}+\mathrm{A} \cdot \overline{\mathrm{~B}}
\end{aligned}$
$\begin{array}{|c|c|c|} \hline A & B & Y \\ \hline 0 & 0 & 1 \\ \hline 1 & 0 & 1 \\ \hline 0 & 1 & 1 \\ \hline 1 & 1 & 0 \\ \hline \end{array}$

JEE Main Physics practice question on Semiconductors (Logic gates), with the answer and a step-by-step solution. Scan a question from your own book or paper to get a whiteboard video.